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daser333 [38]
2 years ago
5

Name

Mathematics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer:

3 bars

Step-by-step explanation:

Total no. of gold bars = 24.

Fraction of bar captain allocated to himself = 1/3 of the bars

no. of bars he allocated to himself =  1/3 of 24 = 1/3 * 24 = 8

Fraction of bar captain allocated to his friend bill = 1/4 of the bars

no. of bars he allocated to his friend bill =  1/4 of 24 = 1/4 * 24 = 6

No . of bars captain allocated to rest of crew = 7

Total no of bars which are allocated altogether =

no. of bars he allocated to himself +no. of bars he allocated to his friend bill +No . of bars captain allocated to rest of crew

substituting the value of above summation variable as calculated above we have

Total no of bars which are allocated altogether = 8+6+7 = 21

No. of bars left = total no. of bars - Total no of bars which are allocated altogether = 24 - 21 = 3

Thus 3 gold bars are left.

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