Name

Mathematics

1 answer:

PtichkaEL [24]3 years ago

8 0

Answer:

3 bars

Step-by-step explanation:

Total no. of gold bars = 24.

Fraction of bar captain allocated to himself = 1/3 of the bars

no. of bars he allocated to himself = 1/3 of 24 = 1/3 * 24 = 8

Fraction of bar captain allocated to his friend bill = 1/4 of the bars

no. of bars he allocated to his friend bill = 1/4 of 24 = 1/4 * 24 = 6

No . of bars captain allocated to rest of crew = 7

Total no of bars which are allocated altogether =

no. of bars he allocated to himself +no. of bars he allocated to his friend bill +No . of bars captain allocated to rest of crew

substituting the value of above summation variable as calculated above we have

Total no of bars which are allocated altogether = 8+6+7 = 21

No. of bars left = total no. of bars - Total no of bars which are allocated altogether = 24 - 21 = 3

Thus 3 gold bars are left.

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$\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ \stackrel{\textit{using this one}}{4p(y- k)=(x- h)^2} \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

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