Answer:
n = (m-1)/(4-g)
Step-by-step explanation:
m= 4n-gn+1
Subtract 1 from each side
m-1= 4n-gn+1-1
m-1 = 4n -gn
Factor out n
m-1 = n(4-g)
Divide each side by (4-g)
(m-1)/(4-g) = n(4-g)/(4-g)
(m-1)/(4-g) = n
n = (m-1)/(4-g)
no u can only buy 6, or u dont have enough money for 7
The answer is definitely B
This is the commutative property (of addition, but this applies to multiplication as well)
It doesn't matter which order the numbers are added in, the same result will be achieved.
1+2 = 2+1
2*4 = 4*2
19 comes next in the series, followed by two 21s.
