Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / 
~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer: Breaks in the word 2016 what do you mean
Explanation:
Charles, a security analyst, needs to check his network for vulnerabilities. he wants a scan that interacts with network nodes and repairs security issues found. The kind of scanning that best describes Charles's requirements is: Active scanning.
<h3>Who is a Security Analyst?</h3>
A Security Analyst's responsibilities include the following:
Define, plan, execute, maintain, and improve security measures, policies, and controls. Writing reports and offering insights on the effectiveness of current security policies, incident response plans, disaster recovery plans, and other security-related information
Active scanning is a scanning approach that involves scanning individual endpoints in an IT network in order to retrieve more specific information.
Learn more about Security Analysts:
brainly.com/question/16354463
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Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
