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Bezzdna [24]
3 years ago
11

in a class, 1/5 of the students have blue eyes. If there are 20 students in the class how many have blue eyes?

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0
4 students have blue eyes.

Working Out:
20 / 5 = 4
Kazeer [188]3 years ago
5 0

Answer:

4 Students

Step-by-step explanation:

20 divided by 5 is 4

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Square root means 46225^1/2 so the answer is 65
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BRAINLIEST AND 10+POINTS! :)
BartSMP [9]

Answer: D.

Step-by-step explanation:

The associative property of addition states that numbers can be added together regardless of how they are grouped.

Answer A shows a property of multiplication.

Answer B shows the additive identity property.

Answer C shows the commutative property.

However, answer D shows that the numbers can be added regardless of how they are grouped.

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A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam
bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against  H_1 if obs.T > t_{\alpha /2;n-1}

here obs.T=1.879

\therefore obs.T \ngtr 2.447=t_{0.025;6}

we accept H_o:\mu _{1}=\mu_{2} at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

1.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2}) independently

We want to test H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}

define D_i=X_i-Y_i , i=1(1)8

now D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8

the hypothesis becomes

H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0
3 years ago
PLEASE ANSWER, EASY QUESTIONS, WILL GIVE BRAINLIEST IF RIGHT 1. Jenny has some tiles in a bag. The tiles are of three different
mash [69]

Answer:

Jenny Question Answer: 4 over 50

Jake Question Answer: 20 beads are red

Step-by-step explanation:

Jenny: She pulled a purple tile 4 times when there is 50 tiles in the bag

Jake: 6 of the 15 beads are red. 6/15 = 2/5 = 40% are red. Take the percent times the total number of beads. 40 * 50 = 20.

20 of the beads are red

I hope I helped, please correct me if I'm wrong!

7 0
3 years ago
AMC 10/12 Student Practice Questions
a_sh-v [17]

Answer:

\mathrm{C.\:}25

Step-by-step explanation:

Notice how each congruent square is divided into four equal parts. Since each square has four parts and there are four squares, there are 16 of these parts in total. Because each of these parts make up \frac{1}{4} of each square, all parts are equal. Therefore, you can count the total number of shaded parts to get your percentage.

The top left and bottom right both have one part shaded each for a total of 2 parts.

The top right and bottom left have 0.5 and 1.5 parts shaded, respectively, for a total of 2 parts.

Therefore, in total, there are 2+2=4 parts shaded out of 16 total parts.

Thus, the percentage of the total area that is shaded is:

\frac{4}{16}=\frac{1}{4}=\fbox{$25\%$}.

3 0
3 years ago
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