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Bezzdna [24]
3 years ago
11

in a class, 1/5 of the students have blue eyes. If there are 20 students in the class how many have blue eyes?

Mathematics
2 answers:
bekas [8.4K]3 years ago
6 0
4 students have blue eyes.

Working Out:
20 / 5 = 4
Kazeer [188]3 years ago
5 0

Answer:

4 Students

Step-by-step explanation:

20 divided by 5 is 4

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Please help me I will give as much points as I can
iVinArrow [24]

Answer:

1/5 = .2

1/65 = 0.1538461538

13MPH

Step-by-step explanation:

(1/5)/(1/65)

5 0
3 years ago
Laura spent 78.5% of her paycheck on her mortgage payment. If her paycheck was $1562 how much was her mortgage?
torisob [31]

Answer:

$337.12

Step-by-step explanation:

Multiply $1562 by 78.5% (or 0.785) =1230.88

Then subtract the percent of her paycheck spent (1230.88) from the total of her paycheck(1562) to find out how much is missing(the mortgage payment)

1562-1230.88=337.12

5 0
3 years ago
700 is 35% of what number??
harina [27]

Answer:

245

Step-by-step explanation:

35                    x

-------             --------

100               700

then you cross multipy and you get

24500

------------------

100

cross out the zeros

and get 245

8 0
3 years ago
Find the volume of the rectangular prism.
algol13

Answer: 105

Step-by-step explanation: 3 x 7 x 5= 105

3 0
3 years ago
Read 2 more answers
What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7
cestrela7 [59]

Answer:

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

Step-by-step explanation:

We need to find the solution for x in the given equation.

\sqrt{9x+7} +\sqrt{2x}=7

Solving:

Subtract \sqrt{2x} from both sides

\sqrt{9x+7} =7-\sqrt{2x}

Taking square on both sides

(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation  \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764

Putting values and solving

x=\frac{-(-980)\pm\sqrt{(-980)^2-4(49)(1760)}}{2(49)}\\x=\frac{980\pm\sqrt{614656}}{98}\\Solving\\x=18 \,\, and x =2

Verifying the solution by putting values of x in given equation

Putting x=18

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(18)+7} +\sqrt{2(18)}=7\\\sqrt{169} +\sqrt{36}=7\\13+6=7\\19\neq 7

So, x=18 is not solution o given equation.

Putting x = 2

\sqrt{9x+7} +\sqrt{2x}=7\\\sqrt{9(2)+7} +\sqrt{2(2)}=7\\\sqrt{25} +\sqrt{4}=7\\5+2=7\\7=7

So, x=2 satisfies the equation

The solution is x =2 for the given equation \sqrt{9x+7} +\sqrt{2x}=7

7 0
3 years ago
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