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3 years ago

621/87 can anybody help me

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

5 0

Answer:

621/87=7.13793103448

Step-by-step explanation:

I divided it and got this answer

Artist 52 [7]3 years ago

3 0

Answer: 621 divided by 87 is 7 with the remainder of 12.

Step-by-step explanation:

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Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t

Yanka [14]

Answer:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

$\hat p=\frac{X}{n}$ estimated proportion of scissors selected for each friend

$p_o=\frac{1}{3}=0.333$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:

Null hypothesis: $p\geq 0.333$

Alternative hypothesis: $p < 0.333$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

6 0

4 years ago

Please help me with please solving for x and y

beks73 [17]

Answer:

first put in equation

Step-by-step explanation:

put the whole thing in a equation

4 0

3 years ago

Read 2 more answers

The lines intersect at point K.

Anvisha [2.4K]

23 is the answer!!!

3 0

3 years ago

A farmer uses 1/3 of his land to grow corn, a quarter of his land to grow lettuce, and 12.5% of his land to grow green beans. He

RUDIKE [14]

I'm going to convert 12.5% to a fraction, which is 12 1/2. Find the denominator for 1/3 and 1/2 which is 6. 1/3 x 2 = 2/6 and 1/2 x 3 = 3/6. Add them all together. 12 3/6 + 2/6 + 7 = around 19.8 ~ 20 acres

5 0

3 years ago

The owner of a catering company wants to select a random sample of clients to find out about their food preferences.

ELEN [110]

Random sampling is defined as a method of selecting a sample from any population in such a way that every selected sample had a predetermined probability of being selected.

So,the true statements for this scenario are :

The owner chooses 20 of the slips of paper without looking.

The owner sends a survey to all clients whose phone number ends in 5.

8 0

4 years ago

Read 2 more answers