If

is invertible, then we can simply choose

because for any invertible matrix

by definition we must have

.
We have

, as

which means

is non-singular and has an inverse. The inverse itself would be
Answer:
semiannually = $1609.77
monthly = $1128.71
Step-by-step explanation:
Could you make the picture clear and back it up a little then i will see it better
Sin 30 = 1/2
tan 45 = 1
Cosec 60 = 2 / √3 = 2√3 / 3
cot 45 = 1
Cos 60 = 1/2
sec 30 = 2 / √3 = 2√3 / 3
_______________________________
[ 1/2 + 1 - 2√3/3 ] ÷ [ 1 + 1/2 - 2√3/3 ] = <em>1</em>
The face and denominator of the fraction are exactly the same thus the answer is 1 .
<span>251×263=66013, which is proof 66013 is not a prime.</span>