In triangle ABC, Aat the top of the triangle, B at 90° and C at the third end, angle C = 21°, the hypotenus = 15m,find BC = y th
e unknown side
1 answer:
Answer
Step-by-step explanation:
Law of sines: SinB/15 = SinA/BC
B = 90
A = 180-90-21=69°
BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m
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