Multiply the expression 2y√2y^ by the expression 4√5y, and write the expression in simplified radical form.

Mathematics

1 answer:

GuDViN [60]3 years ago

4 0

Answer:idk

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\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
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\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
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