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N76 [4]
3 years ago
14

The large decorative storage unit needs to be updates, painted, and re-

Mathematics
1 answer:
Simora [160]3 years ago
3 0

Answer:

idk

Step-by-step explanation:

<h2>idk                                             </h2>
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11. Rocco and Biff are two koalas sitting at the
bagirrra123 [75]

Answer:

Biff's tree is 14 m off the ground and Rocco's tree is 7 m off the ground.

Step-by-step explanation:

Let the height of Biff's tree be represented by x, so that the height of Rocco's tree is \frac{x}{2}.

Draw a straight line from Rocco's point of view to a point t to the middle of Biff's tree. This line divides x into two equal parts, and the angle is divided into 35^{0} each.

By alternate angle property,

Tan  35^{0} = \frac{\frac{x}{2} }{10}

\frac{x}{2} = Tan  35^{0} × 10

  = 7.00021

⇒       x = 2 × 7.0021

            = 14. 0042

         x = 14

Therefore, Biff's tree is 14 m off the ground and Rocco's tree is 7 m off the ground.

5 0
3 years ago
Read 2 more answers
For a standard normal distribution, which of the following variables always equals 0? Mu Sigma x z
Oksi-84 [34.3K]

The mean will always equal 0.

The variable for the mean is μ

5 0
4 years ago
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What is nine tenths-two sixths
MrMuchimi

Answer:

2

Step-by-step explanation:

if you get a pizza and cut it to 9 pieces you get 2 slices the fraction is 9/2

4 0
3 years ago
Which one do you guys think?
anyanavicka [17]

The dice can roll a 1, 2, or 3 out of 6 options to be less than 4. That's 3/6 or 1/2.

5 0
3 years ago
Help! Hurry! NO SPAM!!!! I will mark brainliest if you get it correct, and show your work. Identify the equation for the circle
kotegsom [21]

First we compute the distance between the center and the given point which is exactly the radius

r =

\sqrt{(x2 - x1) + (y2 - y1)}  =  \sqrt{9 - 3 + 11 - 7}  =  \sqrt{10}

Now that we know the center and the radius, we can write the equation of a circle with given radius and center:

{(x - h)}^{2}  + {(y - k)}^{2}  =  {r}^{2}

where (h,k) represent the coordinates of the center (3,7).

We substitute and obtain

{(x - 3)}^{2}  + {(y - 7)}^{2}  =  { \sqrt{10} }^{2} \\  {(x - 3)}^{2}  + {(y - 7)}^{2}  =  10 \\  {x}^{2}  - 6x + 9 +  {y}^{2}  - 14y + 49 = 10 \\  {x}^{2}  +  {y}^{2}  - 6x - 14y + 48 = 0

4 0
3 years ago
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