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vovikov84 [41]
3 years ago
7

Question 4 (3 points)

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

Answer:

The vertical one is the y axis and the horizontal one is the x axis.

Step-by-step explanation:

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4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the
s2008m [1.1K]

Answer:

\frac{x^2}{25} +\frac{y^2}{16} =1

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = 2a

where a is called the semi-major axis.

In this case since the major axis is equal to 10 units:

10=2a

solving for the semi-major axis a :

a=10/2\\a=5

and also the minor axis of an ellipse is represented as:

Minor axis = 2b

where b  is called the semi-minor axis.

Since the minor axis has a length of 8 units:

8=2b

solving for b:

b=8/2\\b=4

Now we can use the equation for an ellipse centered at the origin (0,0):

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

and substituting the values for a and b:

\frac{x^2}{5^2} +\frac{y^2}{4^2} =1

and finall we simplify the expression to get the equation of the ellipse:

\frac{x^2}{25} +\frac{y^2}{16} =1

5 0
3 years ago
Which is the value of x
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16.5 is what I got for x you add them up and equal them to 180 because its a straight line
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3 years ago
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Sketch the triangle in the coordinate plane whose vertices are (0, -2), (2, 3).
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B is the right thing 15 squints
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(Help!!!) Match the sequence (term) with the correct type of sequence (definition).
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Here are the answers:

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2) A

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Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
tester [92]

Given:

Polynomial is 3x^2+15x-56.

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

3x^2+15x-56+(x-8)^2

=3x^2+15x-56+x^2-2(x)(8)+8^2    [\because (a-b)^2=a^2-2ab+b^2]

=3x^2+15x-56+x^2-16x+64

On combining like terms, we get

=(3x^2+x^2)+(15x-16x)+(-56+64)

=4x^2-x+8

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