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rusak2 [61]
3 years ago
15

Find the value of x a) 1 b) 31 c) 24 d) 14

Mathematics
1 answer:
Furkat [3]3 years ago
6 0

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>4</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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Customers of a phone company can choose between two service plans for long distance calls. The first plan has a 26
Wittaler [7]
26+0.08x=8+0.13x
26-8=0.13x-0.08x
18=0.05x
x=18/0.05=360 min
6 0
3 years ago
Read 2 more answers
find two numbers that round to 15.5 when rounded to the nearest tenth. besides 15.04 15.55 15.508 15.445 15.0 15.49
Kitty [74]
Two other numbers are 15.48 and 15.52
4 0
3 years ago
Can u help solve for x 3(x-4)-12=2(x-6)+8
Igoryamba

Answer:

{ \rm{3(x - 4) - 12 = 2(x - 6) + 8}} \\  \\   { \rm{3x - 12 - 12 = 2x - 12 + 8}} \\  \\ { \rm{3x - 24 = 2x - 4}} \\  \\ { \rm{3x - 2x = - 4 + 24}} \\  \\ { \rm{x = 20}}

4 0
2 years ago
Help me solve for k please anyone
kobusy [5.1K]

Answer:

Rounding the the nearest tenth then it is 3.5

Step-by-step explanation:

7 0
2 years ago
Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+
Hoochie [10]
The vertex form of the equation of a parabola is given by

y-k=a(x-h)^2

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

y-(-2)=a(x-(-12))^2 \\  \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\  \\ y=ax^2+24ax+114a-2 \\  \\ y=x^2+24x+ \frac{114a-2}{a}

For a = 1,

y=x^2+24x+112

<span>The parabola whose minimum is at (−12,−2) is given by the equation y=x^2+ax+b, where a = 24 and b = 112.</span>
8 0
3 years ago
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