All categories

3 years ago

Mark filed a claim after his car was rear-ended by another driver. Which

Mathematics

1 answer:

Fofino [41]3 years ago

3 0

Answer: A. He would not have to pay

Step-by-step explanation:

You might be interested in

What is the simple subject of I could feel the rain on my left shoulder.

ahrayia [7]

This a dang easy question. Ask yourself,what is the sentence about?

7 0

3 years ago

What is 2/3 as a decimal?

jolli1 [7]

The closest you can get to a 2/3rds decimal is 0.66 and that goes to infinity.

It is a never ending decimal.

5 0

3 years ago

Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl

brilliants [131]

Answer:

$(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ$

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

$m\angle 9 =80^\circ\\m\angle 5 =55^\circ$

$m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\$

$m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)$

Also

$m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\$

4 0

3 years ago

Read 2 more answers

Find the x and y intercepts of the graph of the equation y=x^2-5

mr_godi [17]

Answer:

x intercepts -sqrt(5), + sqrt(5)

y intercept -5

Step-by-step explanation:

y = x^2 -5

to find the x intercept set y=0 and solve for x

0 = x^2-5

add 5 to each side

5 = x^2

take the square root of each side

+- sqrt(5) = sqrt(x^2)

x = +-sqrt(5) there are 2 x intercepts since it is a quadratic

to find the y intercept set x=0 and solve for y

y = 0-5

y = -5

8 0

3 years ago

How do you solve this ?

TEA [102]

$JK=9x-11\\KL=5x+2\\JL=(9x-11)+(5x+2)=(9x+5x)+(-11+2)=14x-9\\\\JK+KL=JL\\\\\text{substitute}\\\\14x-9=10x+7\ \ \ \ |+9\\\\14x=10x+16\ \ \ \ |-10x\\\\4x=16\ \ \ \ |:4\\\\x=4\\\\JK=9x-11\to JK=9(4)-11=36-11=25$

4 0

3 years ago