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Brut [27]
4 years ago
10

what is the value of 1/6 (square root of 36÷3 to the power of negative two) + 4 to the power of three ÷|-8|

Mathematics
1 answer:
Nikitich [7]4 years ago
6 0
The answer is to that question is 9.
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What is the value of x in the solution to this system of equations?<br> y = x + 1<br> y = 5x + 13
barxatty [35]

Step-by-step explanation:

y=x+1

y=5x+13

=13x/1

=5x/x

5 0
3 years ago
Three classes of school children are selling tickets to the school play. The number of tickets sold by these classes, and the nu
Westkost [7]

Answer:

The expression for the average number of tickets sold per school child is:

M = \frac{tickets*class1 + tickets2*class2 + tickets3*class3}{class1 + class2 + class3}

Step-by-step explanation:

The average number of tickets sold per school child is the weighted mean calculus between the number of tickets sold by these classes and the number of children in each classes.

This is the multiplication between the number of tickets sold by these classes and the number of children in each classes divided by the total weight(in this exercise, the total weight is the total number of school child).

So, the expression for the average number of tickets sold per school child is:

M = \frac{tickets*class1 + tickets2*class2 + tickets3*class3}{class1 + class2 + class3}

3 0
3 years ago
2.8 x 100 miles high. What is the approximate area of wyoming?
zavuch27 [327]

Assuming a regularly shaped rectangle, the formula for the area is given as:


A = L * W


where L and W are the length and width respectively


A = 3.6 x 10^2 miles * 2.8 x 10^2 miles


A = 100,800 square miles


or


A = 10.08 x 10^2 miles 


Read more on Brainly.com - brainly.com/question/5836344#readmore

3 0
3 years ago
To the nearest tenth of a centimeter, what is the circumference of a circle with a radius of 2.5 cm?
IceJOKER [234]
The answer is C≈15.71cm
4 0
3 years ago
What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the
Tasya [4]

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

4 0
4 years ago
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