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Mazyrski [523]
3 years ago
9

What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the

nearest tenth.

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

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ind the surface area of a sphere with a radius of 12 cm. Approximate as 3.14 and round your answer to the nearest hundredth
Bezzdna [24]
The surface area of a sphere is:

A=4πr^2, if r=12 and π is approximated as 3.14 then

A≈4(3.14)(12^2)

A≈4(3.14)(144)

A≈576(3.14)

A≈1808.64 cm^2
5 0
3 years ago
(12x2)/2+1!!!!!!!!!!!!!!
jeka57 [31]

Answer:

13

Step-by-step explanation:

(12*2)/2+1 > 24/2+1 > 12+1 > 13

5 0
3 years ago
I need help with this 13÷65=
ZanzabumX [31]

Answer: 0.2 fam §(* ̄▽ ̄*)§

4 0
3 years ago
Help me please ASAP
Mashutka [201]

Answer: \frac{5}{35}

Step-by-step explanation:

Since, the total number of contestant = 7,

Thus, the probability that out of 3 contestant, me and my friend is chosen

= \frac{2_C_2\times 5_C_1}{7_C_3}

= \frac{\frac{2!}{2!0!}\times \frac{5!}{1!\times 4!}}{\frac{7!}{4!\times 3!}}

= \frac{1\times 5}{\frac{7\times 6\times 5\times 4!}{4!\times 6}}

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4 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply.<br><br>log 2 - log 6
Marina CMI [18]

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :

\log(\frac{m}{n}) = \log m - \log n

\log x^n = n\log x

Use the above rule to solve the expression:

\log 2 -\log 6 = \log \frac{2}{6} = \log \frac{1}{3}   [∴\log(\frac{m}{n}) = \log m - \log n ]

or

\log 2 -\log 6 =\log 2+ \log 6^{-1} = \log 2 + \log \frac{1}{6}     [∴\log x^n = n\log x ]

or

value of : log 2 -log 6 = 0.30102999566 - 0.77815125038 = -0.47712125472



7 0
3 years ago
Read 2 more answers
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