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Mazyrski [523]
3 years ago
9

What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the

nearest tenth.

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

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6yr

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7t

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an original piece of artwork is 3 feet by 2.5 feet. A reprint of the artwork is 6 inches by 5 inches. Are the pieces similiar? I
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Answer:

Yes

Explaination:

They are similar and the ratio is still the same. The artwork's shape didn't change we just resized it by multiplyting its length and width by 2.

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3 years ago
Somebody please help me with this !!!
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Step-by-step explanation:

Case 1 :

3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x =  \frac{6 - 2y}{3}  = \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) + y = 2 \\ 8 -  \frac{8y}{3}  + y = 2 \\  - 1.67y =  - 6 \\

y = 3.59 \\ x = 2 -  \frac{2y}{3}  \\x =  2 -  \frac{2 \times 3.59}{3}  \\  \\ x =  - 0.39

Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

7 0
3 years ago
Are 5.5 + 2.1x + 3.8x - 4.1 and 1.4 5.9x equivalent
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5.5 + 2.1x + 3.8x - 4.1

5.5-4.1 +x(2.1+3.8)

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these are equivalent if there is a plus sign between  1.4 5.9x


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3 years ago
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Estefani‘s house is at point E (3,-2) and Jasmin’s house is at point J (-5,3). Jasmin’s house is the Mid-point of Estefani’s hou
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The formula for midpoint is

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Look at the image below to see the line segment of Estefani's (A), Jasmin's (M), and Preston's (B) houses. Keep in mind that the segment shown below is not accurate in regards to how the line segment formed by Estefani's, Jasmin's, and Preston's houses. It is simply there so you can picture the segment better.

In this case:

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^^^Plug in these number into the formula given above...

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The coordinate of Preston's house is:

(-13, 8)

Hope this helped!

~Just a girl in love with Shawn Mendes

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