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Mazyrski [523]
3 years ago
9

What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the

nearest tenth.

Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

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1.5 hours

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1/2 + 1/2 + 1/2 =1.5

7 0
2 years ago
Please help, will mark Brainly and if you need help with anything I’ll help with any work you send
inessss [21]

Answer:

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3 years ago
Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts
nignag [31]

Answer:

30 + 0.05x < 60

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Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

C(x) = 30 + 0.05x

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

C(x) < 60

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The solution is:

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5 0
2 years ago
I need help understanding how to solve this problem.
LUCKY_DIMON [66]

Answer:

  • <u><em>D. (-5/13, -12/13)</em></u>

Explanation:

It is indicated to <em>find the coordinates</em> of the <em>point T (5/13, 12/13) </em>at a distance <em>π + x.</em>

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Then, the distance π+ x means that the <em>point T</em> is rotated 180º.

The rule for the rotation of a point 180º around the origin is:

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Applying that rule to the point T:

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6 0
3 years ago
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Cooper drove his car for 2 hours at a constant speed of 60 miles per hour and then for another 30 minutes at a constant speed of
murzikaleks [220]
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