Answer:
The percentage of people having cholera is 89.19%.
Step-by-step explanation:
According to the Bayes' theorem the total probability of <em>A</em> is:
![P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})](https://tex.z-dn.net/?f=P%28A%29%3DP%28A%7CB%29P%28B%29%2BP%28A%7CB%5E%7Bc%7D%29P%28B%5E%7Bc%7D%29)
Let <em>X</em> = a person has chorea and <em>Y</em> = the test is positive.
Given:
![P(X^{c}|Y)=0.05\\P(X|Y^{c})=0.12\\P(Y)=0.93](https://tex.z-dn.net/?f=P%28X%5E%7Bc%7D%7CY%29%3D0.05%5C%5CP%28X%7CY%5E%7Bc%7D%29%3D0.12%5C%5CP%28Y%29%3D0.93)
The value of
is:
![P(X|Y)=1-P(X^{c}|Y)=1-0.05=0.95](https://tex.z-dn.net/?f=P%28X%7CY%29%3D1-P%28X%5E%7Bc%7D%7CY%29%3D1-0.05%3D0.95)
Compute the value of P (X) as follows:
![P(X)=P(X|Y)P(Y)+P(X|Y^{c})P(Y^{c})\\=(0.95\times0.93)+(0.12\times(1-0.93))\\=0.8835+0.0084\\=0.8919](https://tex.z-dn.net/?f=P%28X%29%3DP%28X%7CY%29P%28Y%29%2BP%28X%7CY%5E%7Bc%7D%29P%28Y%5E%7Bc%7D%29%5C%5C%3D%280.95%5Ctimes0.93%29%2B%280.12%5Ctimes%281-0.93%29%29%5C%5C%3D0.8835%2B0.0084%5C%5C%3D0.8919)
The percentage of people suffering form cholera is, 0.8919 × 100 = 89.19%.
Thus, the percentage of people having cholera is 89.19%.
Answer:
y=3/2x+1
Step-by-step explanation:
y-4= -⅔(x-6)
y-4=-⅔x+4
y=-⅔x+4+4
(equation of line 1) y= -⅔x+8 gradient= -⅔
(line 2)gradient=3/2
note* the gradients of perpendicular lines multiplied result to -1
gradient=<u>y²-y²</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
<u>3</u><u> </u>=<u>y</u><u>+</u><u>2</u>
<u> </u><u> </u>2. x+2
multiply both sides by 2(x+2)to remove the denominators
3(x+2)=2(y+2)
3x+6=2y+4
3x+6-4=2y
3x+2=2y
divide all sides by 2
3/2x+1=y
y=3/2x+1
There is no image or equation that can be read There for this question is imcomplete.
Addition is needed because of the subtraction sign.