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dusya [7]
3 years ago
9

What is the solution to the system of linear equations graphed below?

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0
Answer is 0,4 hopefully it helps
gregori [183]3 years ago
5 0

Answer:

The answer is (1/2,4)

Step-by-step explanation:

I just did it in Engenuity

Hope it helps

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Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0
3 years ago
A student has some​ $1 and​ $5 bills in his wallet. He has a total of 15 bills that are worth ​$35. How many of each type of bil
Bumek [7]
He has 5 $5 bills and 10 $1 bills because 5x5=25 and 10x1=10. to check the answer you add 25+10=35.
5 0
3 years ago
What is the next term in the geometric sequence 4, -12, 36
Ilia_Sergeevich [38]
The sequence is to multiply by -3.  Therefore, you want to multiply by -3 which gives you 108.  Since it is a negative by a positive the answer would be negative.  The next term would be -108.
7 0
3 years ago
Solve the system of equations by transforming a matrix representing the system of equation into reduced row echelon form.
Gekata [30.6K]

Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

3 0
3 years ago
With an interest rate of 3.25% over 4 years, how much money was originally deposited if
padilas [110]
Interest = Principle(Rate)(Time)
$84.50 = P(0.0325)(4)
$84.50 = P(0.13)
$84.50/0.13 = P
P = 650

$650 was originally deposited.
6 0
3 years ago
Read 2 more answers
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