Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
Can someone help me please?
1 answer:
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Answer:
3rd option
Step-by-step explanation:
Using the identities
cot x =
csc² x = 1 + cot² x
Given
tanθ = , then cotθ =
csc²θ = 1 + ( )² = 1 +
=
cscθ = ± = ±
Since θ is in 3rd quadrant, then cscθ < 0
cscθ = - ×
= -