All categories

3 years ago

Evaluate using factors:(7.62)² - (2.38)²?

Mathematics

2 answers:

Hoochie [10]3 years ago

8 0

Answer:

52.4.

Step-by-step explanation:

This is the difference of 2 squares:

a^2 - b^2 = (a - b)(a + b)

(7.62^2 - (2.38)^2

= (7.62 - 2.38)(7.62 + 2.38)

= 5.24 * 10

= 52.4

Blizzard [7]3 years ago

6 0

Answer:

52.4

Step-by-step explanation:

a²-b² = (a-b)(a+b)

Similarly,

(7.62)²-(2.38)²

= (7.62-2.38)(7.62+2.38)

= (5.24)(10)

= 52.4

You might be interested in

A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil

Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 20 children

r = number of success = none of the 20 children

p = probability of success which in our case is probability that

children are unvaccinated, i.e; p = 13.5%

Let X = Number of children that are unvaccinated

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

P(X = 0) = $\binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}$

= $1\times 1 \times 0.865^{20}$

= 0.055

Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

8 0

3 years ago

What number is a factor of 4 and a multiple of 36

yan [13]

Answer:

$108 \ \\ \ is \: a \: multiple \: of \: 36$

8 0

3 years ago

Read 2 more answers

Three vertices of a rectangle are given. Find the coordinates of the fourth vertex.

kykrilka [37]

The distance between (2,5) and (6,1) is:

$\sf Distance = \sqrt{\left( 6 - 2 \right)^2 + \left( 1 - 5 \right)^2} \\\\ =\sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

The distance between the fourth vertex and (4,-1) should also be 4√2

The only point that gives us that distance is B. (0,3)

$\sf Distance = \sqrt{\left( 4 - 0 \right)^2 + \left( -1 - 3 \right)^2} \\ \\= \sqrt{ 16 + 16} \\ \\ = \boxed{\bf{4 \sqrt{ 2 } }}$

Your final answer is B. (0,3)

5 0

3 years ago

Need help on this one please help thank you I don’t get it

vagabundo [1.1K]

Answer:

g(x) = -2x - 2

Step-by-step explanation:

g(x) = f(x) - 1

= -2x - 2 {the pattern of function graph moving up and down}

6 0

3 years ago

For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative

trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = $-8(1)+0(3)+1(-3)\\= -11$

Projection of U on V = $\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }$

Similarly projection of V on U

= $\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }$

4 0

3 years ago

Evaluate using factors:(7.62)² - (2.38)²​?

Evaluate using factors:(7.62)² - (2.38)²?