3 years ago

Will get the brainiest answer for this problem involving a number line!

Mathematics

1 answer:

nalin [4]3 years ago

4 0

Answer:

6
1/15
13/15

Step-by-step explanation:

The fill-in for the first box is found by counting spaces between 0 and 2/5. There are 6 of them.

Since 6 spaces = 2/5, the value of 1 space is 1/6 of 2/5. We must multiply 2/5 by 1/6 to find the value of 1 space:

1 space = (2/5)(1/6) = 2/30 = 1/15

This is the number that goes in the second box.

To find the value of x, count all the spaces. There are 13, so the value of x is 13 times the value of 1 space:

x = 13(1/15) = 13/15

This is the number that goes in the last box.

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Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")