0.63 does not simplify at all, so it stays 63/100. :)
(i) The simultaneous equations in a, b and c are a+b+c = 7 , 4a+2b+c = 9 & 9a+3b+c = 13
(ii) Expression for nth term = n²-n+7
The first three terms of the sequence are 7, 9, 13
nth term = an²+bn+c
If we put n = 1 then,
1st term = a(1)²+b+c
⇒ a+b+c = 7 ......(1)
If we put n = 2 then,
2nd term = a(2)²+b×2+c
⇒ 4a+2b+c = 9 ........(2)
3rd term = a(3)²+b×3+c
⇒ 9a+3b+c = 13 .......(3)
Multiplying 4 with (1) and subtract (2) from (1) we get,
(4a+4b+4c)-(4a+2b+c)=28-9
⇒ 4a+4b+4c-4a-2b-c=19
⇒ 2b+3c=19 .....(4)
Multiplying 9 with (1) and subtract (3) from (1) we get,
(9a+9b+9c)-(9a+3b+c)=63-13
⇒ 9a+9b+9c-9a-3b-c=50
⇒ 6b+8c=50
⇒ 3b+4c=25 .....(5)
Multiplying 3 with (4) and multiplying 2 with (5), then subtract (5) from (4),
3(2b+3c)-2(3b+4c)=57-50
⇒ 6b+9c-6b-8c=7
⇒ c = 7
From (5),
3b+28 = 25
⇒ 3b = -3
⇒ b = -1
From (1),
a+(-1)+7 = 7
⇒ a-1=0
⇒ a=1
So, nth term = n²-n+7
Learn more about sequence here :
brainly.com/question/6561461
#SPJ10
Answer:
42.12cm²
Step-by-step explanation:
Firs well have to find the hypotenuse of the big and small right angled triangles because it is the length of the long and short diagonals which is needed in solving
The bigger triangle
Using Pythagoras theorem
let the length be x
x²=10²+6²
x²=100+36
x²=136
√x²=√136
x=√136
x=11.7m
The smaller triangle
Using Pythagoras theorem
let the length be y
y²=6²+4²
y²=36+16
y²=52
√y²=√52
y=√52
y=7.2
Now to find the total area of the shape which is a kite
Formula=
1/2 x D1 x D2
D1 is the long diagonal which is the hypotenuse of the bigger triangle and D2 is the shorter diagonal the hypotenuse of the smaller triangle
<h2>
<em>OladipoSeun</em><em>♡˖꒰ᵕ༚ᵕ⑅꒱</em></h2>
Standard form is just the number. The answer is 405.
The circumference is defined to be c=2πr. where the circumference is equal to 2 times pi times the radius
