Answer:
a) To increase 160 by 4% we multiply by 1.04
b) To decrease 160 by 6% we multiply by 0.94
Step-by-step explanation:
a) Here we have to increase 160 by 4% we are to note that;
Therefore, increasing 160 by 4% is to add additional 0.04×160 to 160
That is 160 + 0.04×160 = 160×(1 + 0.04) = 160×1.04
Therefore Sue should have multiplied 160 by 1.04 to increase 160 by 4%.
b) Here to decrease 160 by 6%, we subtract 6% of 160 from 160 that is;
Decrease 160 by 6% = 160 - 160×0.06 = 160×(1 - 0.06) = 160 × 0.94 = 150.4
Hence to decrease 160 by 6% we multiply by 0.94.
3+2=5
25÷5=5
5×3=15
There are 15 Orange picks.
First you add the numbers
6/2*3
Now you calculate the expression
6/2*3
The answer is 9, therefore 9 is your answer
Answer:
Keith's unit rate of change of dollars with respect to time is $1500.
Step-by-step explanation:
It is given that Keith is saving money for a car.
Year 1: 1500
year 2: 3000
year 3: 4500
Let y be the saved amount after x year.
The coordinate pairs according to the given table are (1,1500), (2,3000) and (3,4500).
The formula for rate of change is
Consider any two coordinate pairs.
Let as consider (1,1500) and (2,3000). So, Keith's unit rate of change of dollars with respect to time is
Therefore, Keith's unit rate of change of dollars with respect to time is $1500.
The graph that matches the given equation is y≥x-1 is Graph A.
Option: C.
<u>Step-by-step explanation:</u>
The given equation y≥x-1 is a linear inequality equation.
Graphing Linear Inequalities differs from graphing regular linear equations. That is it has certain rules to be followed to draw the graph.
- First, rearrange the equation as y in the left and other terms in the opposite side.
- Check for the line: y= , y≤ and y≥ comes with straight line where as y< and y> comes with a dotted line.
- Shading: If y> greater than or y≥ greater than or equal is present then the space above the line has to be shaded. If y< less than or y≤ less than or equal is present then the space below the line has to be shaded.
For the given equation y≥x-1,
The line will be solid passing through (0,-1) and (3,2) since it has y≥. Also, the region above the line is shaded.
So the graph A is the graph that matches the equation y≥x-1.
