Answer:
can you expand on your question?
I think the order should be 2-1-3-4, but the description of step 1 is confusing. In selection sort, you iterate from the point of the marker down through the entire list and find the smallest value, and swap that with the value at the marker. Then you advance the marker and repeat the process on the remainder of the list.
Figure 1: An image — an array or a matrix of pixels arranged in columns and rows.
In a (8-bit) greyscale image each picture element has an assigned intensity that
ranges from 0 to 255. A grey scale image is what people normally call a black and
white image, but the name emphasizes that such an image will also include many
shades of grey.
Figure 2: Each pixel has a value from 0 (black) to 255 (white). The possible range of the pixel
values depend on the colour depth of the image, here 8 bit = 256 tones or greyscales.
A normal greyscale image has 8 bit colour depth = 256 greyscales. A “true colour”
image has 24 bit colour depth = 8 x 8 x 8 bits = 256 x 256 x 256 colours = ~16
million colours.
Answer:
Option B (Static NAT) would be the correct choice.
Explanation:
- Static NAT seems to be a method of NAT methodology used to navigate as well as monitor internet usage from some kind of specific public IP address to something like a private IP address.
- Everything always allows the provision of web access to technology, repositories including network equipment inside a protected LAN with an unauthorized IP address.
Some other decisions made aren't relevant to the situation in question. So the above alternative is indeed the right one.
Answer:
Explanation:
Go and ask a teacher or search