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Elenna [48]
3 years ago
10

You have been tracking how much you spend on gas every month for several months and found that on average you spend about $60 pe

r month. If you had to guess, what would you expect the IQR (Interquartile Range) of your gas spending to be? Would $1, $5 or $100 be most logical? Give statistical reasoning to back up your answer.
Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer: $5

Step-by-step explanation: The interquartile range (IQR) refers to the difference between the upper(75%) quartile and lower(25%) quartile of a distribution. Hence, ensuring that the middle 50% is being captured. With the average given as $60, having a interquartile range capturing the middle 50% as $1 seems so small from a statistical stand point. Similarly, an interquartile range of $100 capturing the middle 50% is also too large and nearly impossible if the average price is $60. However, a price of $5 sit well in between considering the average price of $60

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In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
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Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

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C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

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3 years ago
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12,871 rounded to nearest thousand = 13,000.

6281 rounded to nearest thousand = 6,000.

5146 rounded to nearest thousand = 5,000.

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