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WINSTONCH [101]
3 years ago
7

2x+4y+8=0 y x+2y−4=0

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer: https://mathsolver.microsoft.com/en/solve-problem/2x+4y-8=0

Step-by-step explanation: you should find your answer there

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Write a problem that uses a fraction greater than 1.
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A bag contains n white tiles and five black tiles. The tiles are all equal in shape and sizes. A tile is drawn at random and is
pochemuha

We know that our bag has n white tiles and 5 black tiles.

So, the total number of tiles in the bag is n + 5.

We know that a tile is drawn at random and is replaced, then a second tile is drawn.

a) We want to find the probability that the first tile is white.

Because all the tiles have the same probability of being randomly drawn, the probability of drawing a white tile is just the quotient between the number of white tiles and the total number of tiles in the bag.

P = n/(n + 5)

And for the second draw, we do not have any restrictions, so the probability is the above one.

P = n/(n + 5)

b) Now we want both tiles to be white.

For the first one we already know the probability, which is:

P = n/(n + 5)

And because the tile is replaced, the probability of drawing a white tile again is exactly the same:

Q =n/(n + 5)

The joint probability (the probability of both of these outcomes to happen together) is the product of the individual probabilities.

Probability = P*Q = (n/(n + 5))^2

If you want to read more about probability, you can read:

brainly.com/question/24256398

8 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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