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den301095 [7]
3 years ago
14

indictate which of the following are propositions.For the ones which are propositions, determine the truth value.(a) The integer

24 is prime.(b) Is the integer 3​15​ even?(c) The sum of 3 and 4 is 12.(d)
Mathematics
1 answer:
Semmy [17]3 years ago
6 0

Answer:

Step-by-step explanation:

When we propose an hypothesis, it is either true or false. The same goes for a proposition.

The required objective here is to determine the truth value in the following proposition.

(a) The integer 24 is prime.

(b) Is the integer 3​15​ even?

(c) The sum of 3 and 4 is 12.

(d) -4 ∈ Ζ

From the first option:

(a) The integer 24 is prime.

The sentence is a proposition but the truth value is FALSE because a prime number is a number that can only be divide by 1 and itself but in the case of 24, Its factors include  1,2,3,4,6,8,12 and 24 which make 24 to falsify the proposition of being  a prime number.

(b) Is the integer 3​15​ even?

This option is not a proposition but rather a question since it has a question mark, however, 315 is an odd number since it is not divisible by 2.

( c)  The sum of 3 and 4 is 12.

This is a proposition and the truth value is FALSE

The sum of 3+4 = 7  ; Hence; 7 ≠ 12

(d)   -4 ∈ Ζ

This is a proposition and the truth value is TRUE.

-4 ∈ Ζ  is read as ( minus four is an integer  (∈)  of Z )

Yes, this is a proposition and its Truth value is TRUE , since  minus four is an integer  (∈)  of Z

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Answer:

<u>Yes</u>

Step-by-step explanation:

<u>When there are 2 rows</u>

  • Number of erasers per row =  No. of erasers / No. of rows
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  • Number of erasers per row = 9

<u>When there are 3 rows</u>

  • Number of erasers per row =  No. of erasers / No. of rows
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1 year ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

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