The price could go up, it might not work then later down the road
The answer & explanation for this question is given in the attachment below.
Answer:
4
Explanation:got it right on edg.
Answer:
import java.util.Scanner;
import java.lang.*;
class Main
{
public static void main(String args[])
{
int n;
//For capturing the value of n
Scanner scanner = new Scanner(System.in);
System.out.println("Enter the value of n:");
//The entered value is stored in the var n
n = scanner.nextInt();
int k=1;
printnum(n,k);
}
public static void printnum(int n,int k)
{
if(n%2==0)
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
else
{
for(int i=k;i<=n-1;i=i+2)
{
System.out.print(i);
}
System.out.println("");
}
n--;
if(n<=1)
{
System.exit(0);
}
else
{
printnum(n,k+1);
}
}
}
Explanation:
The program is self explanatory.
Answer:
function sum(number) {
if (number == 1) {
return 1;
}
return number + sum(number -1);
}
Explanation:
This is a recursive function, it means that is a function that calls itself for example: if you call the function with sum(5) the process is :
sum(5)
|______ 5 + sum(4)
|_______ 4 + sum(3)
|______ 3 + sum(2)
|_____2 + sum(1)
|_____ 1
the result is 1+2+3+4+5 = 15
