Answer:
Option A(True) is the correct answer for the above question.
Explanation:
- The flowchart is used to give the solution of a problem through the diagram in a step by step processor. It helps the user to understand the solution easily. For diagram, it uses many types of symbols that are fixed for every sequence just like An oval symbol represents the start and end of the flowchart which is fixed for every flowchart.
- So for the decisions in a flowchart, the diamond symbol is used which is to make the decisions and it has two sides-- one is true and the other is false.
- The decisions are used also to represent the loop structure which is also called the repetition structure because the loop is controlled by the help of decisions so the diamond box is also used for the loop
- The above question-statement says that the decisions-controlled is used for the loop and for the decisions which are true because it is also described above.
Answer:
Salting is the preservation of food with dry edible salt. It is related to pickling in general and more specifically to brining also known as fermenting (preparing food with brine, that is, salty water) and is one form of curing.
Explanation:
Answer:
The second one:
int sum = 0; for (int i = 0; i < values.length; i++) { if ((values[i] % 2) == 0) { sum += values[i]; } }
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
Answer:
- low = 10
- high = 50
- count = 0
-
- for i in range(low, high + 1):
- if(i % 3 == 0 and i % 5 == 0):
- count += 1
- print(count)
Explanation:
The solution code is written in Python.
We can create low and high variables to store the lower bound and upper bound in the range (Line 1-2)
Next create a counter variable, count (Line 3).
Use a for loop to traverse through the number between lower bound and upper bound and check if the current number-i is divisible by 3 and by 5, increment the count by one.
After the loop, print the count and we can get the number of ideal integers within the range (Line 8).
