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kakasveta [241]
3 years ago
9

PLZ HELP ME !!!! Which expressions below equal a rational number ? Choose ALL that apply !

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0

Answer:

The correct option is are 2, 3 and 4.

Step-by-step explanation:

Rational number: If a number can be defined in the form of p/q where, p and q are integers and q≠0, then it is known as rational numbers. For example: 0.2, 1/3 and 1 etc.

Irrational number: If a number can not be defined in the form of p/q where, p and q are integers and q≠0, then it is known as irrational numbers. For example: 0.222..., √2 and π etc.

\pi\sqrt{36}=6\pi

It is an irrational number because π is an irrational number.

7\sqrt{5}-\sqrt{245}=7\sqrt{5}-7\sqrt{5}=0

It is a rational number.

\frac{4}{5}+\frac{3}{8}=\frac{32+15}{40}=\frac{47}{40}

It is a rational number.

(4\sqrt{7})(2\sqrt{7})=(4\times 2)(\sqrt{7\times 7})=8(7)=56

It is a rational number.

\sqrt{100}+\sqrt{5}=10+\sqrt{5}

It is an irrational number because sum of a rational and an irrational number is always an irrational number.

Therefore the correct option is are 2, 3 and 4.

Yakvenalex [24]3 years ago
4 0

(From top to bottom) wrong, right, right, right, wrong. This is because a irrational*an irrational number is rational, but a rational*an irrational is an irrational number

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820

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Suppose that the duration of a routine doctor's visit is known to be normally distributed with a mean of 21 minutes and a standa
vazorg [7]

Answer:

33.36% probability that it lasted at least 24 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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If one of the visits is randomly chosen, what is the probability that it lasted at least 24 minute?

This is 1 subtracted by the pvalue of Z when X = 24. So

Z = \frac{X - \mu}{\sigma}

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33.36% probability that it lasted at least 24 minutes

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