To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
(-4)^-3 = 
-4^-3 = 
Basically in this situation there is no difference whether parenthesis are used or not.
Answer:
18
Step-by-step explanation:
Divide with by paratheses first. Use PEMDAS method
F(x)=-1x-1
1) Pick 2 points on the line (i chose (-4,3) and (3,-4)
2) Find slope of the line using the 2 points. (work below)
3) Find y-intercept, which is the point where y-axis and the line cross (y-intercept is -1).
4) Place both slope and y-intercept into slope-intercept form, y=mx+b (m=slope and b=y-intercept.)
5) Change y to f(x) (meaning function of x).
Work:
3-(-4)/-4-3=3+4/-4-3=7/-7=-1
y-intercept equals -1 also.
y=mx+b
y=-1x+(-1)
y=-1x-1
f(x)=-1x-1<---Answer
