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attashe74 [19]
3 years ago
10

What is the perimeter of the framed picture in terms of x? ( x + ) inches

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

jjytrewasxcfgyuikjyt45678ijhgfgn

Step-by-step explanation:

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Which value is equivalent to
Ksenya-84 [330]

Answer:

\frac{25}{144}

Step-by-step explanation:

(\frac{7 * 5 * 2}{7 * 3} )^2 * (\frac{5^0}{2^-3})^3 * 2^{-9}

Simplified becomes;

(\frac{10}{3})^2 * 2^3 * \frac{1}{2^9}

Simplifying further gives; \frac{25}{144}

6 0
3 years ago
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title="\frac{3}
Scrat [10]
The answer would be 14/15

Find a common denominator that both of the fractions can use. An easy way to do this is simply multiply the denominators together. So for 3/5 you would multiply by 3 to get the fraction 9/15 and then multiply 1/3 by 5 to get 5/15. Add both 9/15 and 5/15 to then get 14/15.
4 0
3 years ago
Read 2 more answers
Miguel bikes 23 km per hour and starts at mile 10. Gabby bikes 28 km per hour and starts at mile 0. Which system of linear equat
7nadin3 [17]
The correct answer is D) Miguel:  d=23t+10, Gabby d=28t

We multiply the speed of each person by t, the amount of time.  This is where the 23t in Miguel's equation and the 28t in Gabby's equation come from.  The starting point is added to this, which leads to 23t+10 and 28t+0 or 28t.
8 0
3 years ago
Read 2 more answers
A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty
Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: \hat{p}=0.84

Significance level : \alpha= 1-0.98=0.02

Critical z-value : z_{\alpha/2}=2.33  (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}

i.e. \approx0.84\pm 0.085

i.e. (0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0
4 years ago
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