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mamaluj [8]
3 years ago
9

I'm confused. Can someone help?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

================================================

b.

The polynomial y^2-10y+23 cannot be factored

The perfect square trinomial is y^2-10y + 25

---------

Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

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PLEASE HELP ME!!!!!!!!!!!
Ahat [919]

Answer:

I'm not sure

Step-by-step explanation:

3 0
3 years ago
Select all the pieces of the triangle that are marked as congruent in the following picture
nikitadnepr [17]

Answer:

C. D. E. is the correct answer.

Step-by-step explanation:

Hope this helps you. Have a nice day. If you have doubt then please ask in comments.

Please mark as brainliest. It helps a lot.

5 0
3 years ago
Read 2 more answers
Find the side length of the square
IgorLugansk [536]

the answer is 30.3

hope it helps

8 0
3 years ago
NEED HELP WITH BOTH PLZ
Natalija [7]
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
7 0
4 years ago
I really need help with this one
Novay_Z [31]

Answer:

28

Step-by-step explanation:

Since B is the midpoint of AC, that means AB = BC. That means 3x+4 = 5x-6. We can now set up an equation to solve for x:

3x+4 = 5x-6

3x+10 = 5x

10 = 2x

x = 5

Now that we know what x is, we can just plug x into the expression of AB and multiply it by 2:

(3*(5)+4)*2

=(15+4)*2

=19*2

=28

(side note: we could have plugged x into the expression of BC as well, but in this case plugging it into AB tends to be easier to solve)

Therefore, the length of AC is 28.

3 0
3 years ago
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