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Artist 52 [7]
2 years ago
8

What is 4 divided by 3/4 • [-9] divided by [-4]

Mathematics
1 answer:
Bas_tet [7]2 years ago
3 0

Answer:

I believe the answer is 12

Step-by-step explanation:

4 ÷ 3/4 * -9  ÷ -4

PEMDAS

4  ÷ (3/4 * -9)  ÷ -4

4  ÷ -1/12  ÷ -4

(4  ÷ -1/12)  ÷ -4

-48  ÷ -4 = 12

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PLEASE!! HELP!!
anygoal [31]

Answer:

2nd dot from the left (in the 1.7 column)

Step-by-step explanation:

the square root of 3 is 1.73

each interval on that number line goes by one tenths

(1.1, 1.2, 1.3, etc.)

so counting 7 spaces from the number one should land you at 1.7

(the second red dot from the left)

hope i was able to help!

5 0
3 years ago
How do you calculate the area and the perimeter of a parallelogram and a triangle?
Mnenie [13.5K]

for parallelograms:

area = b(h)

so basically, the length times the height. just like how you would find the area of a square.

perimeter: just add all of the sides together.

for triangles:

area = 1/2(b) x h

so half the length multiplied by the height. for example, if the length was 4, you have to use half of that. so that means 2 times whatever the height is.

perimeter: again, just add all three sides together

7 0
3 years ago
Read 2 more answers
I need help please and thank you
andrew-mc [135]

Answer:

Area will be 2(lb + bh + hl)

So 2*(12*9 + 9*4 + 4*12)

384 sqft

3 0
3 years ago
Read 2 more answers
How do you solve this ?
sesenic [268]
2048
that the answer o think
7 0
3 years ago
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Find all solutions to the equation.<br><br> cos2x + 2 cos x + 1 = 0
yanalaym [24]
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.

So x = pi/2, pi/2 + pi = 3pi/2.

5 0
3 years ago
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