Ask question

Ask question

All categories

3 years ago

13

Your Bank account balance was $235 and 24. After two checks were cashed (each for the same amount) your balance is now -45.58. W

hat was the amount of each of those checks?

1 answer:

elena55 [62]3 years ago

8 0

235.24 + 45.58 = 280.82

280.82/2 = 140.41

each check was for $140.41

You might be interested in

62 is 90.5% of what number?

Reptile [31]

68.5. You take 62 and divide it by the percentage as a decimal, .905. 62 / .905 = 68.5.

6 0

4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=100%20%5Ctimes%2068%20%5Cdiv%2015" id="TexFormula1" title="100 \times 68 \div 15" alt="100 \ti

goldfiish [28.3K]

The answer is 453 rounded

4 0

4 years ago

Explain why the function is discontinuous at the given number

Blizzard [7]

For $f$ to be continuous at $x=5$ , we need to have

$\displaystyle\lim_{x\to5}f(x)=f(5)$

Note that $x\to5$ means that $x\neq5$ , but that $x$ is *approaching* 5. We're told that for $x\neq5$ , we have

$f(x)=\dfrac{x^2-5x}{x^2-25}$

We can write

$\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}$

and the limit would be

$\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)$

and so $f$ is discontinuous.

5 0

3 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

Cho f(t)=(t-4)u(t-2)phep bien doi laplace la<br> F(s)=e^-2s/s^2-2e^-2s/s62

FinnZ [79.3K]

Step-by-step explanation:

cho f(t)=(t-4)u(t-2)phep bien doi laplace la

F(s)=e^-2s/s^2-2e^-2s/s62

4 0

3 years ago