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loris [4]
3 years ago
8

Identify the graph of the equation (x−1)2+(y+3)2=9.

Mathematics
2 answers:
algol133 years ago
7 0

Answer:

5/2

Step-by-step explanation:

VikaD [51]3 years ago
3 0
5/2 it’s going to be your answer I’m so happy that you got your answer congratulations
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In their first year, The Princess Bride earned $342,600,000 while Double-Take earned $670,900,000. What were their total earning
motikmotik

Answer:

1013500000

Step-by-step explanation:

Addition, mate.

8 0
3 years ago
Water pours into a tank at the rate of 2000 cm3/min. The tank is cylindrical with radius 2 meters. How fast is the height of wat
Gennadij [26K]

Volume of water in the tank:

V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h

Differentiate both sides with respect to time <em>t</em> :

\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}

<em>V</em> changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for d<em>h</em>/d<em>t</em> :

2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}

\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}

(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)

7 0
3 years ago
Help me please and thank you.
rusak2 [61]

Answer:the first one

Step-by-step explanation:

i did the math

4 0
3 years ago
Read 2 more answers
Anyone tryna help me
polet [3.4K]

Answer:

y < (3/2) |x - 3| +2

Step-by-step explanation:

4 0
3 years ago
Barbara wants to buy some glittery heart-shaped beads to make friendship bracelets. The beads she wants come in a small pack wit
faust18 [17]

Answer:

The large pack is a better deal!

Step-by-step explanation:

so first we need to figure out how much the individual beads cost.

Small pack: $ 3.60÷90 = 0.04 cents per bead

Large pack: $9.00 ÷ 300 = 0.03 cents per bead

Hope this helps!!

Have a great day!!

8 0
3 years ago
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