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Reil [10]
3 years ago
14

Consider the equation 14*10^0.5w=100

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Step-by-step explanation:

14*10^0.5w=100

14*10^{0.5w}=100

Solve the equation for w

divide by 14 on both sides

10^{0.5w}=\frac{100}{14}

Convert exponential form into log form

base is 10 so we convert into log form

log (a)= x  then a=10^x

10^{0.5w}=\frac{100}{14}

0.5w = log(\frac{100}{14} )\\0.5w = log(\frac{50}{7} )\\\\

divide both sides by 0.5

0.5w = log(\frac{50}{7} )\\\\\\w= 2 log(\frac{50}{7} )

Answer:

w= 2 log(\frac{50}{7} )

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Weights of newborn babies are normally distributed with a mean of 7.452 pounds and
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3 years ago
The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the
12345 [234]

Answer:

4x^2-21x-2

Step-by-step explanation:

Given that:

Difference of two trinomials is x^2 - 10x + 2

One of the two trinomials is  3x^2 - 11x - 4

To find:

The other trinomial = ?

Four options are:

2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2

Solution:

Let the two trinomials be A and B.

Given A - B = x^2 - 10x + 2

B = 3x^2 - 11x - 4

We have to find the other trinomial A.

A - B = x^2 - 10x + 2

A - (3x^2 - 11x - 4) = x^2 - 10x + 2

\Rightarrow A = x^2 - 10x + 2 + (3x^2 - 11x - 4)

\Rightarrow A = 4x^2-21x-2

So, the correct answer is 4x^2-21x-2.

3 0
3 years ago
Write the following relationship as a ratio in simplest form. 18 students out of 42 students
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Answer:

3:7

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
-Dominant- [34]
1) -3(5x+2y=-3)⇒ -15x-6y=9
                                             ⇒ -9x=27
     2(3x+3y=9)⇒ 6x+6y=18

2) -9x/-9=27/-9 ⇒ x=-3 

3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6

Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

6 0
3 years ago
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