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grigory [225]
3 years ago
9

Being nice take the points​

Computers and Technology
1 answer:
MArishka [77]3 years ago
4 0

Answer:

Sure!!! and thank you very much

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The color sensor if i’m correct
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We assume that ABC Corporation has two business offices. These offices are in the cities of Orlando and Miami. These cities are
murzikaleks [220]

Answer:

The following are the answer to the given points:

Explanation:

In point (a):

Calculating the long-distance call cost:

= 4 \times 5 \times 0.40 \\= 20 \times 0.40\\= 8

Calculating the local call cost:

= 10 \times 3  \times 0.05\\ = 30 \times 0.05\\= 1.5

Calculating the overall cost of PSTN:

= 25 + (4 \times 5 \times 0.40) + (10 \times 3 \times 0.05) + 2000 + 275 \\= 25 + 8 + 1.5 + 2000 + 275 \\=   2309.5

In point (b):

Calculating the call rate per second and the average arrival rate:

\to (\lambda) = 0.2

The call average length:

\to (T_s) = - 8  \\\\ = (8  \times 60) \ seconds \\\\ = 480 \ seconds  

The complete agent number:

\to  (m) = 9

The strength of traffic:

\to u = \lambda \times  T_s  \\\\  =   (0.2  \times 480) \\\\ = 96    

The occupancy of the agent:

\to  p = \frac{u}{m}  \\\\

      = \frac{96}{9}  \\ \\= 10.66  

Calculation of obtained:

= \frac{(\frac{um}{m!})}{(\frac{um}{m!})} + (1-p) \sum {m-1} _{k=0}  \ \frac{uk}{k!}

We get = 0.329 to substitute values.  

In point (c):

The rate of blocking = 5 \%

average call time (T_s) = 480 \ seconds

                                    = 0.05 \times  480 \ seconds \\  = 24 \ second

In point (d):

Calculating the number of link, which is required:  

= \frac{275}{5} \\\\ =55

In point (e):

Calculating the Line Number:

= \frac{275}{5} \\\\ =55

PSTN line number:

=  (\frac{2000}{55}) \\\\ = 36.3636\\\\= 37

In point (f):

The gross design expense = $ 2309. 5

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4 years ago
What is the difference between the Paste Special and Paste Link options?
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Paste Link lets you automatically update the referenced document.
8 0
4 years ago
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Html tags are surrounded by which types of brackets​
Rama09 [41]
Right brackets example
5 0
3 years ago
Use a dictionary to count the frequency of letters in the input string. Only letters should be counted, not blank spaces, number
netineya [11]

Answer:

def count_letters(text):

 result = {}

 # Go through each letter in the text

 convert_text = text.lower()

 for letter in convert_text:

   if letter.isalpha():

     if letter in result:

       result[letter] += 1

     else:

       result[letter] = 1

 return result

print(count_letters("AaBbCc"))

# Should be {'a': 2, 'b': 2, 'c': 2}

print(count_letters("Math is fun! 2+2=4"))

# Should be {'m': 1, 'a': 1, 't': 1, 'h': 1, 'i': 1, 's': 1, 'f': 1, 'u': 1, 'n': 1}

print(count_letters("This is a sentence."))

# Should be {'t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}

Explanation:

4 0
3 years ago
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