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grigory [225]
3 years ago
9

Being nice take the points​

Computers and Technology
1 answer:
MArishka [77]3 years ago
4 0

Answer:

Sure!!! and thank you very much

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Using Sequential Search on an array of size n, the search key is definitely present in the array. The probability of matching th
MissTica

Answer:

(11n-5) / 12 is correct answer.

Explanation:

The Probability that key will match to nth term = 1/2

The Probability that key will match to n-1th term = 1/3

As all other probabilities are equal

The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6

The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))

Let P(i) = Probability that key matches to ith index.

The Average time complexity = 22 i=1 P(i) * i

The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2

The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2

The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2

The Average time complexity = (n-1)/12 + (n-1)/3 + n/2

The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12

The Average time complexity = 11n-5 / 12

so (11n-5) / 12 is correct answer.

7 0
3 years ago
The picture that graphically represents the items you use in Windows is called a/an
Novosadov [1.4K]
The answer to this is Bulls icon
6 0
3 years ago
Lower range tones generally require ________ speakers. lower range tones generally require ________ speakers. multiple choice
lilavasa [31]

Lower range tones generally require larger speakers.

It's no secret that lower range tones generally require larger speakers. This is because lower frequencies have longer wavelengths, and thus require more physical space to produce.

While this may seem like a simple concept, there are a few things to keep in mind when it comes to speaker size and low frequency response. First, larger speakers can usually reproduce lower frequencies more efficiently than smaller ones. Second, the size of the speaker's enclosure also plays a role in how well it can reproduce low frequencies.

A larger enclosure will typically have an easier time reproducing low frequencies than a smaller one.

Keep these things in mind when selecting speakers for your system. If you're looking for accurate low frequency reproduction, make sure to choose speakers with larger drivers and enclosures.

Learn more on speakers here:

brainly.com/question/14649463

#SPJ4

6 0
1 year ago
"The goal of this assignment is to give you some experience building a program that uses objects. You will use the BankAccount c
MArishka [77]

Answer:

see explaination

Explanation:

Please find my detailed implementation.

I have tested with Single Bank account object.

You can create array list of Bank Account in test program:

public class BankAccount {

private String name;

private int accountNumber;

private int PIN;

private double balance;

public BankAccount(int accN, int pin) {

accountNumber = accN;

PIN = pin;

}

public BankAccount () {

name = "Undefined";

accountNumber = 0;

PIN = 0;

balance = 0;

}

public String getName() {

return name;

}

public int getAccountNumber() {

return accountNumber;

}

public int getPIN() {

return PIN;

}

public double getBalance() {

return balance;

}

public void setName(String name) {

this.name = name;

}

public void setAccountNumber(int accountNumber) {

this.accountNumber = accountNumber;

}

public void setPIN(int pIN) {

PIN = pIN;

}

public void setBalance(double balance) {

this.balance = balance;

}

public void withdrawal(double amount) {

if(amount <= balance) {

balance = balance - amount;

}

}

public void deposit(double amount) {

balance += amount;

}

public void transferFunds (double amount, BankAccount toBankAccount) {

if(amount >= balance) {

toBankAccount.setBalance(amount + toBankAccount.getBalance());

balance -= amount;

}

}

atOverride //change the at with the at symbol

public String toString() {

return "{id:"+accountNumber+", name:"+name+", pin:"+PIN+", balance:$"+balance+"}";

}

}

#########

public class BankAccountTest {

public static void main(String[] args) {

BankAccount myAccount = new BankAccount(526323450, 1234);

myAccount.setName("Pravesh");

myAccount.setBalance(345.64);

System.out.println(myAccount);

BankAccount anotherAccount = new BankAccount(); //default constructor

System.out.println(anotherAccount);

}

}

3 0
3 years ago
Dim Inventory() as Integer = {357, 126, 220}Call Stock(Inventory(2),Me.lblOutput)Sub Stock (ByVal Number As Integer, ByRef lblLa
aalyn [17]

Answer:

The answer is "Option c".

Explanation:

In the given visual basic code, an integer array "Inventory" is declared, that includes 3 elements, that are "357, 126, and 220". In the next line, a call stock function is used, in the function, the array is passed as a parameter and in array parameter, the index value that is "2" is passed. This function use label to print array index value, that is "220". and other options are incorrect that can be described as follows:

  • Option a and Option b both are wrong because array indexing always starts with 0 and ends with n-1, and in this array, it will take index value 2, which is not equal to 357 and 126.

6 0
3 years ago
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