A) 390/.3= 1300 , 1300-390= 910, 910/1300= .70 OR 1.00-.3= .7
b) 390/.3= 1300$
c)390/.3= 1300 , 1300-390= 910$
<u>Answer:</u>
A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.
<u>Solution:</u>
We need to show that the gradient of the curve at A is 1
Here given that ,
--- equation 1
Also, according to question at point A (b+1,0)
So curve at point A will, put the value of x and y

0=b+1-c --- equation 2
According to multiple rule of Differentiation,

so, we get



By putting value of point A and putting value of eq 2 we get


Hence proved that the gradient of the curve at A is 1.
18. It would be the second graph. The third graph is eliminated as the boy takes a time period to shave, which means there should be a constant point (horizontal line) right after the first incline. The first one is eliminated as the boy takes a bath which requires another constant point in the graph.
19.
C
E
D
A
B
Definition of quadratic a formula
= a formula that gives the solutions of the general quadratic equation ax2 + bx + c = 0 and that is usually written in the form x = (-b ± √(b2 − 4ac))/(2a)