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gladu [14]
3 years ago
12

Java code?????

Computers and Technology
1 answer:
12345 [234]3 years ago
5 0

Answer:

Explanation:

Here is the code for you:

import java.io.*;

import java.util.*;

class GirlScoutCookies

{

public static void main(String[] args)

{

int [] BoxesCategory = new int[5];

Scanner sc = new Scanner(System.in);

System.out.print("Total number of girls in the troop: ");

int numOfGirlScouts = sc.nextInt();

for(int i = 0; i < numOfGirlScouts; i++)

{

System.out.print("Boxes of cookies for girl #"+(i+1)+": ");

int boxes = sc.nextInt();

if(boxes >= 0 && boxes <= 10)

BoxesCategory[0]++;

else if(boxes >= 11 && boxes <= 20)

BoxesCategory[1]++;

else if(boxes >= 21 && boxes <= 30)

BoxesCategory[2]++;

else if(boxes >= 31 && boxes <= 40)

BoxesCategory[3]++;

else if(boxes > 40)

BoxesCategory[4]++;

}

System.out.println("TOTAL BOXES\tNUMBER OF GIRL SCOUTS");

System.out.println(" 0 to 10\t"+BoxesCategory[0]);

System.out.println("11 to 20\t"+BoxesCategory[1]);

System.out.println("21 to 30\t"+BoxesCategory[2]);

System.out.println("31 to 40\t"+BoxesCategory[3]);

System.out.println("41 or more\t"+BoxesCategory[4]);

}

}

And the sample output is:

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For example, 01110100 in binary is 116 in decimal:

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Class A: Uses the first 8 bits for the Network portion leaving 24 bits for host IDs. The leftmost bit is set to “0”.

Class B: Uses the first 16 bits for the Network portion leaving 16 bits for host IDs. The two leftmost bits are set to “10”.

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End address: 192.168.58.16 – 2 = 192.168.58.14

Broadcast address: 192.168.58.16 – 1 = 192.168.58.15

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