Answer: np.random.uniform(0,1,100)
Explanation:
import numpy as np
#pass the random uniform generated array into x
x = np.random.uniform(low, high, size)
#here low = 0, high = 1, size = 100
x = no.random.uniform(0,1,100)
Answer:
Actions that Bobbi should take to identify opportunities for online business growth are:
Review competitor websites
Identify a USP
Build a SWOT analysis
Explanation:
The first thing Bobbi should do is to review competitor website.
This will give her information about her competitors the products that they offer, the price of their products, the website layout and structure of the competitors, any strategy they are using to boost their online product sale such as by offering product promotion, discounted price etc.
After reviewing competitor websites, next thing that Bobbi should do is identify a Unique Selling Proposition. Bobbi should identify the unique features, benefits of her products that induce her business to stand out from the competitors. Identify all those unique aspects and factors that make her product different from others.
After identifying USP, Bobbi should now build a Strengths, Weaknesses, Opportunities and Threats (SWOT) analysis. This way she will be able to recognize and understand her website's strengths, distinctive competencies, limitations, opportunities and risks. This will help her to analyse the overall strategic position of her website as well as her business. That will help her create a strategy for the future.
Answer:
hope this helps. I am also a learner like you. Please cross check my explanation.
Explanation:
#include
#include
using namespace std;
int main()
{
int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0
int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.
int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.
q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]
*q=1
; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one
p = a; //p is now holding address of complete array a
*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one
int*& r = p; //not sure
int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q
r = *s + 1; //not sure
s= &r; //explained above
**s = 1; //explained above
return 0;
}
Answer:
D
Explanation:
A zero-day vulnerability is a computer-software vulnerability that is unknown to those who would be interested in mitigating the vulnerability. Until the vulnerability is mitigated, hackers can exploit it to adversely affect computer programs, data, additional computers or a network. An exploit directed at a zero-day vulnerability is called a zero-day exploit, or zero-day attack.
Answer:
The description for the given question is described in the explanation section below.
Explanation:
Since deviance constitutes a breach of a people's current standard. I believe Erickson's psychological concept that Deviance becomes a trait that is commonly considered to need social control agencies' intervention, i.e. 'Something must being done'.
- There most probably resulted whenever the rules governing behavior appear inconsistent in just about any particular frame.
- Therefore the principle of this theory is that even in the analysis of deviance this same significant point seems to be the social community, instead of the participant.
