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LenaWriter [7]
3 years ago
6

The difrent between valid deductive argument and strong inductive argument? At least 2 example​

Computers and Technology
1 answer:
Artemon [7]3 years ago
5 0

Answer:

If the arguer believes that the truth of the premises definitely establishes the truth of the conclusion, then the argument is deductive. If the arguer believes that the truth of the premises provides only good reasons to believe the conclusion is probably true, then the argument is inductive.

ALSO

Deductive arguments have unassailable conclusions assuming all the premises are true, but inductive arguments simply have some measure of probability that the argument is true—based on the strength of the argument and the evidence to support it.

Explanation:

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Exam Instructions
SIZIF [17.4K]

A diagram which indicates the sequence in which milk travels through a production plant to each stage of a cheese manufacturing process is: D. A process schedule

<h3>What is a process schedule?</h3>

A process schedule can be defined as a type of diagram (schematic) which is designed and developed to illustrate the various processes and stages (steps) that are associated with manufacturing of a particular product.

In this context, a process schedule is a diagram which would most likely indicate the sequence in which milk travels through a production plant to each stage of a cheese manufacturing process.

Read more on cheese manufacturing here: brainly.com/question/21148228

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7 0
1 year ago
______ is a certification program that recognizes sustainable building practices and strategies. Question 1 options: A) Brundtla
Pani-rosa [81]

Answer:

(C) LEED

Explanation:

LEED certification is a recognized worldwide as symbol of viability achievement.

(Leadership in Energy and Environmental Design(LEED):- It is the most popular and widely used rating system in the world for green buildings. Available for almost all building project types, including new constructions to interior fit-outs.

8 0
3 years ago
Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,
nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
  3. P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
  4. P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
  5. P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
  3. P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
  4. P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
  5. P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
  6. P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

  1. P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
  2. P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
  3. P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
  4. P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
  5. P5 will not be allocated to any of the available space because none can contain it.
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

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3 years ago
Variables make it easier to do what?
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<span>D. Make changes to your code
Variables allow the ability to easily substitute numbers for other numbers.
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3 years ago
An effective team would never have ______.
inysia [295]
An ineffective leader
3 0
3 years ago
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