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3 years ago

Write each as an algebraic expression

Mathematics

1 answer:

erik [133]3 years ago

3 0

Answer:

4^3

11>6

y>2

13-x

Step-by-step explanation:

4 is to the third power

11 is greater than 6 which means u use this sign >

y is greater than 2

13 subtract x

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Solve: In 2x + In 2 = 0<br> DONE

pychu [463]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

We can use some logarithmic rules to solve this easily.

<em>Note: Ln means $Log_e$ </em>

<em />

Now, lets start with the equation:

$ln(2x) + ln(2) = 0\\ln(2x) = -ln(2)$

Writing left side with logarithmic base e, we have:

$Log_{e}(2x) = -ln(2)$

We can now use the property shown below to make this into exponential form:

$Log_{a}b=x\\means\\a^x=b$

So, we write:

$Log_{e}(2x) = -ln(2)\\e^{-ln(2)}=2x$

We recognize another property of exponentials:

$a^{bc}=(a^{b})^{c}$

So, we write:

$e^{-ln(2)}=2x\\(e^{ln(2)})^{-1}=2x$

Also, another property of natural logarithms is:

$e^{(ln(a))}=a$

Now, we simplify:

$(e^{ln(2)})^{-1}=2x\\(2)^{-1}=2x\\\frac{1}{2}=2x\\x=\frac{\frac{1}{2}}{2}\\x=\frac{1}{4}$

This is the answer.

7 0

3 years ago

The mathematics class took an educational field trip. There were 360 total students in buses and vans. If each bus holds 55 stud

saveliy_v [14]

I think if you take 360 and divide it by 55 thats how many busses they used. Then take that answer and divide it by 13 to find how many vans were used.

5 0

3 years ago

"what quadrant is...." PLEASE PLEASE HELP!!!! Thank you so so much!!! *will give brainliest*

sdas [7]

Given:

$\tan \theta > 0$ and $\sec \theta$ .

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only $\sin \theta, \text{cosec}\theta$ are positive and others are negative.

In III quadrant, only $\cot \theta, \tan\theta$ are positive and others are negative.

In IV quadrant, only $\cos \theta, \sec\theta$ are positive and others are negative.

We have,

$\tan \theta > 0$ and $\sec \theta$ .

Here, $\tan \theta$ is positive and $\sec \theta$ is negative. So, $\theta$ lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

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3 years ago

What is the solution to the equation m/m+4 +4/4-m = m^2/ m^2- 16 ?

nignag [31]

The answer is 2 i think

7 0

3 years ago

Read 2 more answers

Someone please help me!

Radda [10]

Answer:

dude don't you have notes

Step-by-step explanation:

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3 years ago