Answer:
y= 1/3x +3
Step-by-step explanation:
slope: 4-1/3-(-6) =3/9=1/3
point slope: y-4=1/3(x-3)
y-4=1/3x -1
y=1/3x +3
Answer:
9 and 11 are prime
Step-by-step explanation:
The can't be evenly divided by 2
Answer:
(P(t)) = P₀/(1 - P₀(kt)) was proved below.
Step-by-step explanation:
From the question, since β and δ are both proportional to P, we can deduce the following equation ;
dP/dt = k(M-P)P
dP/dt = (P^(2))(A-B)
If k = (A-B);
dP/dt = (P^(2))k
Thus, we obtain;
dP/(P^(2)) = k dt
((P(t), P₀)∫)dS/(S^(2)) = k∫dt
Thus; [(-1)/P(t)] + (1/P₀) = kt
Simplifying,
1/(P(t)) = (1/P₀) - kt
Multiply each term by (P(t)) to get ;
1 = (P(t))/P₀) - (P(t))(kt)
Multiply each term by (P₀) to give ;
P₀ = (P(t))[1 - P₀(kt)]
Divide both sides by (1-kt),
Thus; (P(t)) = P₀/(1 - P₀(kt))
Answer:
<em>$ 33.6 to fill this tank, provided a community cost of $2.8 per gallon</em>
Step-by-step explanation:
1. Let us first find the volume of the gas the tank, by the general multiplication of Base * height ⇒ 11 inches * 1.25 feet * 1.75 feet. For the simplicity, we should convert feet ⇒ inches, as such: 1.25 feet = 1.25 * 12 inches = 15 inches, 1.75 feet = 1.75 * 12 inches = 21 inches. Now we have a common unit, let us find the volume ⇒ 11 in. * 15 in. * 21 in. = 3465 inches^3.
2. Let us say that the the average price of gas in my community is $2.8 per gallon. We would first have to convert inches ⇒ gallons provided 1 gallon = 231 inches: 3465/231 = 15 gallons.
4. Now simply multiply this price of 2.8 dollars per gallon by the number of gallons to receive the cost if the tank was full: 2.8 * 15 = <em>$ 42 if this tank was full provided a community cost of $ 2.8 per gallon</em>
5. Now this tank is 20% full, so we must calculate the cost to fill the other 80% up. That would be 80/100 * 42 = 4/5 * 42 = 168/5 = <em>$ 33.6 to fill this tank, provided a community cost of $2.8 per gallon</em>
There ya go that’s on the chart and pretty easy you should try it out it is actually kinda fun