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irina1246 [14]
3 years ago
15

Question in image please help quickly, I'm on a time limit :D

Mathematics
1 answer:
inn [45]3 years ago
4 0

Answer:

By distance formula ,

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-1-5)^2 + (6-3)^2}

AB = \sqrt{36 + 9}

AB = \sqrt{45}

AB = 6.708(approx)

To give answer in 3 significant figures :

AB = 6.70

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I need this answer fast! Please!
vovangra [49]

Answer:

\large\boxed{\begin{array}{c|c|c|c}Length:&4cm&2cm&8cm\\Width:&6cm&12cm&3cm\\Height:&9cm&9cm&9cm\end{array}}

Step-by-step explanation:

The formula of a volume of a cube with side length a:

V=a^3

We have a = 6cm. Substitute:

V=6^3=216\ cm^3

\begin{array}{c|c}216&2\\108&2\\54&2\\27&3\\9&3\\3&3\\1\end{array}

216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2)\cdot(2\cdot3)\cdot(3\cdot3)=4\cdot6\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=2\cdot(2\cdot2\cdot3)\cdot(3\cdot3)=2\cdot12\cdot9\\\\216=2\cdot2\cdot2\cdot3\cdot3\cdot3=(2\cdot2\cdot2)\cdot3\cdot(3\cdot3)=8\cdot3\cdot9\\\vdots

7 0
3 years ago
Morgan is walking her dog on an 8-meter-long leash. She is currently 500 meters from her house, so the maximum and minimum dista
Gnom [1K]
Given:
Morgan = 500 meters from her house
Length of leash = 8 meters

minimum distance of the dog from the house 500 - 8 = 492 meters.
maximum distance of the dog from the house 500 + 8 = 508 meters.
7 0
3 years ago
X-2y=5 2x-4y=10
Nitella [24]

Step-by-step explanation:

X-2y=5 ; 2x-4y=10

• x - 2y = 5 • 2x -4y = 10

-2y = -x+5 -4y= -2x +10

y1 = ½x - 5/2 y2 = ½x -5/2

• => y1 = y2

½x -5/2 = ½x -5/2

the systems have no solution

• graph as attached

8 0
2 years ago
I need helppppppppppppp
ohaa [14]
Simplify

4ax+12-3ax=25+3a

ax+12=25+3a

ax-3a=25-12

a(x-3)=13
5 0
3 years ago
This is a map of three towns. It shows the train line and the highway that connects the towns. The north direction is shown. The
vlada-n [284]

Answer:

  about 106 km

Step-by-step explanation:

The distance between the two towns can be estimated several ways. In the attachment, we chose to measure the angles on the map. Using the law of sines, we can estimate the unknown distance.

The distance can also be estimated using the Tounouse-Avaria distance as a ruler. For best results, that ruler would need to be subdivided to an appropriate level.

__

<h3>angle measures</h3>

The angles in the triangle can be measured using a protractor or some other tool. The attachment shows the results from a geometry program:

  • ∠TMA ≈ 107°
  • ∠TAM ≈ 24°
<h3>law of sines</h3>

The law of sines tells us the distances are proportional to the sines of the opposite angles:

  TM/sin(TAM) = TA/sin(TMA)

  TM = sin(24°)×(250 km)/sin(107°) ≈ 106.3 km

The distance from Tounouse to Mt. Monotti is estimated to be about 106 km.

__

<em>Alternate solution</em>

Using a compass or dividers to project the TM distance onto TA, we find it is between 0.4 and 0.5 of the TA distance. The difference between 2×TM and TA can be estimated to be about 0.4×TM. That is, ...

  TM ≈ TA/2.4 ≈ (250 km)/2.4 ≈ 104.2 km

This estimate is consistent with the one found using angle measures.

4 0
2 years ago
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