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Nady [450]
4 years ago
6

Solve for x: 4x - 12 = 8x + 24

Mathematics
2 answers:
Charra [1.4K]4 years ago
7 0

Answer:

4x-12=8x+12

-24=4x

-6=x

Step-by-step explanation:

put the variables to one side and numbers to the other side

then divide 4 from each side

now you have the answer

s2008m [1.1K]4 years ago
3 0

Answer: -9

Step-by-step explanation:

To solve the equation, isolate the variable, then use basic arithmetic.

Subtract 4x on both sides to obtain the equation:

-12 = 4x + 24

Subtract 24 on both sides to isolate 4x, and obtain the equation:

-36 = 4x

Finally, divide both sides by 4 to obtain the following:

-9 = x

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The graph shows two lines, A and B.
EastWind [94]

Answer:


Part A: one solution:

Part B: x = 3, y = 4.


Explanation:


1) Part A: how many solutions does the pair of equations for lines A and B have?


The solution of a system of equations in a graph is given by the intersetion of the curves that represent the equations.


In this case, there are two straight lines, which intersect in one and only one point.


Hence, the system has one solution.


2) Part B: what is the solution to the equations of lines A and B?


The solution is the pair of coordinates of the intersection point. It is (3, 4).


Therefore, the solution is x = 3, y = 4.

8 0
3 years ago
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Solve: 7m + 12 = −4m + 78
Mandarinka [93]

7m + 12 = -4m + 78

7m + 4m = 78 - 12

11m = 66

m = 6

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4 years ago
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You draw two cards from a standard deck of 52 cards. What is the probability of drawing a queen and then a king consecutively fr
Ksivusya [100]

Answer:

D

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8 0
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Factorise 3x^3 - 12xy^2​
igomit [66]

Answer:

we can conclude that:

3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)

Step-by-step explanation:

Given the expression

3x^3-12xy^2

Let us factorize the expression

3x^3-12xy^2

Apply the exponent rule: a^{b+c}=a^ba^c

3x^3\:-\:12xy^2=3xx^2-12xy^2

Rewrite 12 as 4 · 3

                     =3xx^2-4\cdot \:3xy^2

Factor out the common term 3x

                     =3x\left(x^2-4y^2\right)

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

                      =3x\left(x+2y\right)\left(x-2y\right)

Therefore, we can conclude that:

3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)

8 0
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