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DanielleElmas [232]
3 years ago
10

Tickets for a concert have been in increadbibly high demand. and as the date for the concert draws closer the price of tickets i

ncreases exponentially. the cost of a pair of concert tickets was $96 yesterday and today it is $108.
what is the multiplier

what is the daily percent rate?

using the cost of a ticket today as your initial value write an exponential equation that models this situation

what will be the cost of a pair of concert tickets in one week from today

what was the cost of a pair of tickets three days ago?
Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

  • multiplier 1.125
  • percent rate 12.5%
  • p(t) = 108·1.125^t
  • p(7) = $246.32
  • p(-3) = $75.85

Step-by-step explanation:

a) The daily multiplier is 108/96 = 1.125

b) The daily percentage change is 1.125 -1 = .125 = 12.5%

c) The function can be written as ...

  price = (initial value)·(daily multiplier)^t

  p = 108·1.125^t

d) for t=7, put the number in and do the arithmetic.

  108·1.125^7 ≈ 246.32 . . . dollar cost in a week

e) same deal, for t=-3

  108·1.125^-3 ≈ 75.85 . . . .dollar cost 3 days ago

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Answer:

6+4x-3z

Step-by-step explanation:

<u>-2</u>+6x+z-2x<u>+8</u>-4z

6<u>+6x</u>+z<u>-2x</u>-4z

6+4x<u>+z-4z</u>

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Stephen has a dog that weigths 5 times as much as lan's dog.The total weigths of both dogs is 72 pounds.How much does Stephens d
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Step-by-step explanation:

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3 years ago
Drag each expression to show whether it is equivalent to 36x + 9, 9(4x – 1), or (4 • 9x) + (4 • 2).
lora16 [44]
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The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
AleksandrR [38]

The length of the rectangle = 16 meters

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<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

                             273 = (2x - 5) x

                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

a= coefficient of x^2 = 2

b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

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<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

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                                                = 21 - 5

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