Answer:
SQUARE
Step-by-step explanation:
If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).
Find the following MN, NP, PQ and MQ
Using the formula for calculating the distance between two points
MN = √(6-0)²+(0-4)²
MN = √6²+4²
MN = √36+16
MN = √52
MN = 2√13
NP = √(0-6)²+(-4-0)²
NP = √6²+4²
NP = √36+16
NP = √52
NP = 2√13
PQ = √(-6-0)²+(0-(-4))²
PQ = √6²+4²
PQ = √36+16
PQ = √52
PQ = 2√13
MQ = √(-6-0)²+(0-4)²
MQ = √6²+4²
MQ = √36+16
MQ= √52
MQ = 2√13
Since the length of all the sides are equal, hence the shape is a SQUARE
Think of when If you cross two lines you get a point where they meet
A point is a solution.
So if the lines never cross, then they would have no point, or A, No Solution
Answer:
<em>☆</em><em><</em><em> </em><em><u>《</u></em><em><u>HOPE IT WILL HELP YOU</u></em><em>》</em><em>></em><em>☆</em>
Step-by-step explanation:
Y=1.5x+2
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>1</u></em><em><u>)</u></em></h3>
y=1.5 (1) +2
y=1.5+2
y=3.5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>2</u></em><em><u>)</u></em></h3>
y=1.5(2)+2
y=3+2
y=5
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>3</u></em><em><u>)</u></em></h3>
y=1.5 (3)+2
y=4.5+2
y=6.5
<h3>(x=4)</h3>
y=1.5 (4)+2
y=6+2
y=8
<h3>
<em><u>(</u></em><em><u>x</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em></h3>
y=1.5 (5)+2
y=7.5+2
y=9.5
<h2>
<em><u>please</u></em><em><u> </u></em><em><u>mark my ans as BRAIN</u></em><em><u> </u></em><em><u>LIST</u></em></h2>
Answer:
hiiii
Step-by-step explanation:
welcome back
I think it wold be b
please tell me if i wrong
