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3 years ago

Which unit price is the highest?

Mathematics

2 answers:

BaLLatris [955]3 years ago

7 0

Answer:

pepper for 1.62 per pound

kompoz [17]3 years ago

4 0

Answer: peppers

Step-by-step explanation:

Peppers cost the greatest amount per pound

$1.62 (peppers) > $1.51 (turnips) > $1.48 (celery) > $1.26 (carrots)

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Complete the table of values for y = 6 - 2x

Tpy6a [65]

Step-by-step explanation:

a) substitute x values:

6-2(0) = 6

6-2(1) = 4

6-2(2) = 2

6-2(3) = 0

6-2(4) = -2

6-2(5) = -4

b) rewrite equation as y=-2x+6.

this shows a negative slope with a y-intercept of 6.

c) 3=6-2x

-6 -6

-3 = -2x

divide both sided by 2

-3/-2 = x

3/2=x

5 0

3 years ago

Kim wants to estimate 5.494 + 1.108 by first rounding to the nearest hundredth. Find her mistake and correct it.

alexandr1967 [171]

Umm... not sure what her mistake is, but it should be 5.49+1.11=6.6

7 0

3 years ago

Which accounts of a business can outsiders view

Ainat [17]

Non gap businesses are allowed to be viewed by outsiders

6 0

4 years ago

1. f(−1)

iragen [17]

Ans hb 420

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing

d1i1m1o1n [39]

Answer:

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

Step-by-step explanation:

The first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be $x$ , and the vertical component to be $y$ , then:

• horizontal component ⇒ $sin (15^{\circ}) = \frac{x}{4}$

⇒ $x = 4\space\ sin(15^{\circ})$

⇒ $x \approx \bf 1.04$

• vertical component ⇒ $cos(15^{\circ}) = \frac{y}{4}$

⇒ $y = 4 \space\ cos(15^{\circ})$

⇒ $y \approx \bf 3.86$

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector v (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ $x = 6 \space\ sin (60^{\circ})$

⇒ $\bf 5.2$

• vertical component ⇒ $y = 6 \space\ cos(60^{\circ})$

⇒ $y = \bf 3$

○ For the second vector (magnitude 2):

• horizontal component ⇒ $x = 2 \space\ cos (40^{\circ})$

⇒ $\bf 1.5$

• vertical component ⇒ $y = 2 \space\ sin(40^{\circ})$

⇒ $\bf 1.3$

Now we can add the respective components together:

v = 5.2i + 3j + 1.5i + 1.3j

⇒ (5.2 + 1.5)i + (3 + 1.3)j

⇒ 6.7i + 4.3j

∴ Magnitude of v ⇒ $|v| = \sqrt{(6.7)^2 + (4.3)^2}$

⇒ $|v| \approx \bf 8$

To find the bearing of v, we have to first calculate the angle marked $\alpha$ :

$tan \alpha = \frac{4.3}{6.7}$

⇒ $\alpha = tan^{-1}(\frac{4.3}{6.7})$

⇒ $\alpha = \bf 32.7^{\circ}$

∴ Bearing = 270° + 32.7°

= 302.7°

8 0

2 years ago