Hello
5^(2x) = 27
if : a>0 and b>0 a = b <span>equivalent to log(a) = log (b)
</span> log (5^(2x)) = log(27) ... (1)
a>0 and b>0 log(a^n) = nlog(a)
(1) equivalent to :<span>2x log 5 = log 27</span>
Answer:
x = 4
Step-by-step explanation:
First, you subtract 1 from both sides, giving you 3x = x + 8
Then you subtract 1x from both sides, so 2x = 8
Divide the 2 from both sides which leaves you with the answer, x = 4
Y + R + V = 42
but 4 YEARS AGO : (R-4) +(V-4) = Y
Replace Y in the 1st equation by: (R-4) +(V-4)
(R-4) +(V-4) + R + V = 42
2R - 2V - 8 = 42; 2R -2V = 50, or R+V=25
IF R+V =25 AND Y + R +V = 42, then Y + 25 = 42 and Y =17
C. H
let me know if i'm wrong-
Answer:
x=2 x=-2
Step-by-step explanation:
x² + 2x - 4 = 2x
Subtract 2x from each side
x² + 2x-2x - 4 = 2x-2x
x^2 -4 = 0
Factor
We know this is the difference of squares
(x-2)(x+2) =0
Using the zero product property
x-2 =0 x+2 =0
x=2 x=-2