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svetlana [45]
3 years ago
12

Similarities between inferential and descriptive statistics

Mathematics
2 answers:
quester [9]3 years ago
8 0
Jsjwjsejeiwjsns qisjn
Nady [450]3 years ago
6 0
Both descriptive and inferential statistics rely on the same set of data. Descriptive statistics rely solely on this set of data, whilst inferential statistics also rely on this data in order to make generalisations about a larger population.
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On a farm there are some cows and some chickens if the animals have a total of 40 heads and 112 legs how many cows are there? ho
tankabanditka [31]

Answer:

There are 16 cows and 24 chickens in the farm.

Step-by-step explanation:

A Cow has 4 legs

Chicken has 2 legs.

Lets take there x chickens AND,

there are y number of Cows.

Now we can write two equations for the number of heads and legs.

For the number of heads we can write,

x+y=40 <--------- 1st equation

For the number of legs we can write,

2x+4y=112 <------ 2nd equation

We can now solve the simultaneous equations to find x and y

Multiply 1st equation by 2 and deduct it from 2nd equation to remove x

⇒2x+4y-2*(x+y)=112-80

⇒2x+4y-2x-2y)=112-80

⇒2y=32

⇒y=16

Therefore, there are 16 cows in the farm.

Now we can substitute the y value to the 1st equation and find x value.

x+16=40

x=24

Therefore, there are 24 chickens in the farm.



6 0
3 years ago
What is 2+4+6-9+17-4=x
Karolina [17]

Answer:

x = 16 or 16 = x

Step-by-step explanation:

2+4+6-9+17-4=x

6+6-9+17-4=x

12+17-9-4=x

29-9-4=x

20-4=x

16=x

7 0
3 years ago
Read 2 more answers
stickers are made with the same ratio of width to length. a sticker 2 inches has a length of 4 inches. complete the table
yuradex [85]
2=4, 3=6, 4=8, 5=10
inches will be x and length will be y you multiply x by 2 to get y
7 0
4 years ago
Read 2 more answers
PLEASE HELP ASAP I FORGOT HOW TO DO THIS!
nadya68 [22]

Answer:

its A

Step-by-step explanation:

5 0
4 years ago
Make the appropriate conclusion. Choose the correct answer below. A. RejectReject H0. There is insufficientinsufficient evidence
timama [110]

Answer:

a) Option D is correct.

H0​: μ = 71

Ha​: μ > 71

b) Option F is correct

z > 1.28

c) z = 2.85

d) Option C is correct.

Reject H0.There is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Step-by-step explanation:

a) For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

This question aims to test the the true mean heart rate during laughter exceeds 71 beats per minute.

Hence, the null hypothesis is that there isn't sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute. That is, the true mean doesn't exceed 71 beats per minute.

And the alternative hypothesis is that there is sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute.

Mathematically,

The null hypothesis is represented as

H₀: μ = 71

The alternative hypothesis is represented as

Hₐ: μ > 71

b) Using z-distribution, the rejection area is obtained from the confidence level at which the test is going to be performed. Since the hypothesis test tests only in one direction,

Significance level = (100% - confidence level)/2

0.10 = 10% = (100% - confidence level)/2

20% = 100% - (confidence level)

Confidence level = 100% - 20% = 80%

Critical value for 80% confidence level = 1.28

And since we are testing if the true mean heart rate during laughter exceeds 71 beats per minute, the rejection area would be

z > 1.28

c) The test statistic is given as

z = (x - μ)/σₓ

x = sample mean = 73.4

μ = 71

σₓ = standard error = (σ/√n)

σ = 8

n = Sample size = 90

σₓ = (8/√90) = 0.8433

z = (73.4 - 71) ÷ 0.8433

z = 2.846 = 2.85

d) Since the z-test statistic obtained, 2.85, is firmly in the rejection area, z > 1.28, we reject the null hypothesis, accept the alternative hypothesis and say that there is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Hope this Helps!!!

4 0
3 years ago
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