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3 years ago

Help anyone 8th grade math need it asap

Mathematics

2 answers:

valina [46]3 years ago

8 0

Answer:

$\frac{7}{10}$

PtichkaEL [24]3 years ago

6 0

Answer:

7/10

Step-by-step explanation:

If you move the decimal point to over to the right, also known as multiplying by a hundred, then you get 70. Right now we have 70/100

Simplify even further you would get 7 / 10

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If a point is inside a circle, the distance from the center of the circle to that point ____.

Alenkasestr [34]

Answer:

A. is less than the radius.

Step-by-step explanation:

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The first part is 3. The second is 12

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Use the graph method to solve the system of linear equations:<br><br> 2x + y = 3 and x + y = 3

Igoryamba

It’s (0,3).
If you graph this by hand or using a graphing calculator you can see that the lines intersect at (0,3) so that is your answer

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3 years ago

Determine the resultant of the given vectors by component method. E = 23 km , 11 degrees N of E N = 25 km, 24 degrees E of N G =

boyakko [2]

Answer:

The resultant of the given vectors by component method is $\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$ .

Step-by-step explanation:

First we define each vector by applying using rectangular form:

1) $\|\vec E\| = 23\,km$ , 11º north of east.

$\vec E = 23\,km\cdot (\cos 11^{\circ}\,\hat{i}+\sin 11^{\circ}\,\hat{j})$ (Eq. 1)

2) $\|\vec N\| = 25\,km$ , 24º east of north.

$\vec N = 25\,km\cdot (\sin 24^{\circ}\,\hat{i}+\cos 24^{\circ}\,\hat{j})$ (Eq. 2)

3) $\|\vec G\| = 19\,km$ , 18º south of west.

$\vec G = 19\,km\cdot (-\cos 18^{\circ}\,\hat{i}-\sin 18^{\circ}\,\hat{j})$ (Eq. 3)

4) $\|\vec R\| = 27\,km$ , 58º west of north.

$\vec R = 27\,km\cdot (-\sin 58^{\circ}\,\hat{i}+\cos 58^{\circ}\,\hat{j})$ (Eq. 4)

The resultant of given vectors is determined by vector sum, that is:

$\vec U = \vec E + \vec N + \vec G + \vec R$ (Eq. 5)

$\vec U = 23\,km\cdot (\cos 11^{\circ}\,\hat{i}+\sin 11^{\circ}\,\hat{j})+25\,km \cdot (\sin 24^{\circ}\,\hat{i}+\cos 24^{\circ}\,\hat{j})+19\,km\cdot (-\cos 18^{\circ}\,\hat{i}-\sin 18^{\circ}\,\hat{j})+27\,km\cdot (-\sin 58^{\circ}\,\hat{i}+\cos 58^{\circ}\,\hat{j})$

$\vec U = (23\,km\cdot \cos 11^{\circ}+25\,km\cdot \sin 24^{\circ}-19\,km\cdot \cos 18^{\circ}-27\,km\cdot \sin 58^{\circ})\,\hat{i}+(23\,km\cdot \sin 11^{\circ}+25\,km\cdot \cos 24^{\circ}-19\,km\cdot \sin 18^{\circ}+27\,km\cdot \cos 58^{\circ})\,\hat{j}$

$\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$

The resultant of the given vectors by component method is $\vec U = -8.222\,\hat{i}+35.664\,\hat{j}\,\,\,[km]$ .

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3 years ago

State the inequalities that satisfy the shaded region.

Zielflug [23.3K]

Answer:

Step-by-step explanation:

$\Bigg\{ \begin{array}{ccc}2x-y+1&>&0\\x^2+2x-y-15&\leq &0\\\end {array} \right.$

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3 years ago