What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St
artRoot b squared minus 4 a c EndRoot Over 2 a EndFraction –2 + StartRoot 2 EndRoot 2 – StartRoot 2 EndRoot 1 + StartRoot 2 EndRoot –1 + StartRoot 2 EndRoot
1 answer:
Answer:
See attached for a "Neat" quadratic formula.
a = -1
b = 2
c = 1
x = [-2 +- sqr root( 4 -4*-1*1)] / -2
x = [-2 +- sqr root( 4 -4*-1*1)] / -2
x = [-2 +- sqr root(8)] / -2
x1 = (-2 +2.8284271247) / -2
x1 = .8284271247 / -2
x1 = -0.41421
x2 = (-2 -2.8284271247) / -2
x2 = ( -4.8284271247) / -2
x2 = 2.4142135624
So the equation has the positive solution of
2.4142135624
Step-by-step explanation:
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Answer:
-5 when ...
Step-by-step explanation:
The rules of exponents can help you simplify the given product.
<h3>Rules</h3>(a/b)^c = (a^c)/(b^c)
(ab)^c = (a^c)(b^c)
(a^b)(a^c) = a^(b+c)
(a^b)/(a^c) = a^(b-c)
<h3>Application</h3>
This expression does not match any of those offered.
When x=-1 and y=5, this becomes ...
see the attached figure to better understand the problem
we know that
If a and b are parallel lines
then
m∠1=m∠4 --------> by alternate exterior angles
m∠3+m∠4= --------> by supplementary angles
so
m∠3+m∠1=
therefore
<u>the answer is the option</u>
m∠1 = 110° and m∠3 = 70°
